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How Many Zeros in a Quartic Polynomial?

How many zeros in a quartic polynomial? A quartic polynomial has exactly 4 zeros in the complex number system, counting multiplicity. A quartic has the form f(x) = ax4 + bx3 + cx2 + dx + e (a ≠ 0). For real-coefficient quartics, the real zeros can number 0, 2, or 4. Quartic is the highest degree for which a general algebraic solution formula exists. Related: Polynomial function zeros.

A quartic polynomial has

4

zeros

Written Form
f(x) = ax⁴ + bx³ + cx² + dx + e (where a ≠ 0)
Scientific
Degree 4

The Real/Complex Breakdown for a Quartic

The direct answer: always exactly 4. For real coefficients, the possible distributions are: See also: Even degree polynomial zeros.

How many zeros in a Quartic Polynomial? 4 zeros, written as f(x) = ax⁴ + bx³ + cx² + dx + e (where a ≠ 0) (Degree 4).
How many zeros in a Quartic Polynomial? — howmanyzeros.org
Real vs complex zero distributions for a quartic.
Real zerosComplex zerosExample type
4 distinct real0Graph crosses x-axis 4 times
2 real + 1 repeated real03 distinct intercepts (one tangent)
2 real + 2 complex2Graph crosses x-axis twice
0 real + 4 complex4Graph never crosses x-axis

A quartic can have 0, 2, or 4 real zeros — never 1 or 3, because complex roots come in pairs.

Is Quartic Degree 4 or 5?

Quartic means degree 4, from the Latin quartus (fourth). Degree 5 is quintic.

Quartic
Degree 4 — "quartus," fourth
Biquadratic
A quartic with only even powers (ax4 + bx2 + c), solvable via u = x2

How Do You Find the Zeros of a Quartic Polynomial?

  • Rational Root Theorem + synthetic division: Reduce to a cubic or quadratic
  • Biquadratic substitution: Substitute u = x2 to get a solvable quadratic in u
  • Factoring into two quadratics
  • Ferrari's method: The general quartic formula — the highest degree where such a formula exists

For instance, f(x) = x4 − 5x2 + 4 is biquadratic: substituting u = x2 gives (u − 1)(u − 4) = 0, so x = ±1 and x = ±2 — four distinct real zeros.


Zeros in a Quartic Polynomial: FAQ

Can a quartic have exactly 1 or 3 real zeros?
Quick answer

No — since complex roots come in pairs, the real zero count for a quartic is always 0, 2, or 4.

Who solved the general quartic formula?
Quick answer

Lodovico Ferrari, in the 16th century — his method is the highest-degree general algebraic solution that exists.

What is a biquadratic?

A quartic with only even-power terms (ax4 + bx2 + c), solvable by substituting u = x2.

Can a quartic have zero real zeros?

Yes — for example, f(x) = x4 + 1 has all four zeros complex.

Why is quartic the highest degree with a general formula?

The Abel-Ruffini theorem proves no general radical formula exists for degree 5 and above.